Simplify: y+6/4+y-3/5=5y-4/8 Tiger Algebra Solver (2024)

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

y+6/4+y-3/5-(5*y-4/8)=0

Step by step solution :

Step 1 :

 1 Simplify — 2

Equation at the end of step 1 :

 6 3 1 (((y+—)+y)-—)-(5y-—) = 0 4 5 2

Step 2 :

Rewriting the whole as an Equivalent Fraction :

2.1Subtracting a fraction from a whole

Rewrite the whole as a fraction using 2 as the denominator :

 5y 5y • 2 5y = —— = —————— 1 2 

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

 5y • 2 - (1) 10y - 1 ———————————— = ——————— 2 2 

Equation at the end of step 2 :

 6 3 (10y-1) (((y+—)+y)-—)-——————— = 0 4 5 2 

Step 3 :

 3 Simplify — 5

Equation at the end of step 3 :

 6 3 (10y - 1) (((y + —) + y) - —) - ————————— = 0 4 5 2 

Step 4 :

 3 Simplify — 2

Equation at the end of step 4 :

 3 3 (10y - 1) (((y + —) + y) - —) - ————————— = 0 2 5 2 

Step 5 :

Rewriting the whole as an Equivalent Fraction :

5.1Adding a fraction to a whole

Rewrite the whole as a fraction using 2 as the denominator :

 y y • 2 y = — = ————— 1 2 

Adding fractions that have a common denominator :

5.2 Adding up the two equivalent fractions

 y • 2 + 3 2y + 3 ————————— = —————— 2 2 

Equation at the end of step 5 :

 (2y + 3) 3 (10y - 1) ((———————— + y) - —) - ————————— = 0 2 5 2 

Step 6 :

Rewriting the whole as an Equivalent Fraction :

6.1Adding a whole to a fraction

Rewrite the whole as a fraction using 2 as the denominator :

 y y • 2 y = — = ————— 1 2 

Adding fractions that have a common denominator :

6.2 Adding up the two equivalent fractions

 (2y+3) + y • 2 4y + 3 —————————————— = —————— 2 2 

Equation at the end of step 6 :

 (4y + 3) 3 (10y - 1) (———————— - —) - ————————— = 0 2 5 2 

Step 7 :

Calculating the Least Common Multiple :

7.1 Find the Least Common Multiple

The left denominator is : 2

The right denominator is : 5

Number of times each prime factor
appears in the factorization of:
Prime
Factor
Left
Denominator
Right
Denominator
L.C.M = Max
{Left,Right}
2101
5011
Product of all
Prime Factors
2510


Least Common Multiple:
10

Calculating Multipliers :

7.2 Calculate multipliers for the two fractions

Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno

Left_M=L.C.M/L_Deno=5

Right_M=L.C.M/R_Deno=2

Making Equivalent Fractions :

7.3 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

 L. Mult. • L. Num. (4y+3) • 5 —————————————————— = —————————— L.C.M 10  R. Mult. • R. Num. 3 • 2 —————————————————— = ————— L.C.M 10 

Adding fractions that have a common denominator :

7.4 Adding up the two equivalent fractions

 (4y+3) • 5 - (3 • 2) 20y + 9 ———————————————————— = ——————— 10 10 

Equation at the end of step 7 :

 (20y + 9) (10y - 1) ————————— - ————————— = 0 10 2 

Step 8 :

Calculating the Least Common Multiple :

8.1 Find the Least Common Multiple

The left denominator is : 10

The right denominator is : 2

Number of times each prime factor
appears in the factorization of:
Prime
Factor
Left
Denominator
Right
Denominator
L.C.M = Max
{Left,Right}
2111
5101
Product of all
Prime Factors
10210


Least Common Multiple:
10

Calculating Multipliers :

8.2 Calculate multipliers for the two fractions

Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno

Left_M=L.C.M/L_Deno=1

Right_M=L.C.M/R_Deno=5

Making Equivalent Fractions :

8.3 Rewrite the two fractions into equivalent fractions

 L. Mult. • L. Num. (20y+9) —————————————————— = ——————— L.C.M 10  R. Mult. • R. Num. (10y-1) • 5 —————————————————— = ——————————— L.C.M 10 

Adding fractions that have a common denominator :

8.4 Adding up the two equivalent fractions

 (20y+9) - ((10y-1) • 5) 14 - 30y ——————————————————————— = ———————— 10 10 

Step 9 :

Pulling out like terms :

9.1 Pull out like factors:

14 - 30y=-2•(15y - 7)

Equation at the end of step 9 :

 -2 • (15y - 7) —————————————— = 0 10 

Step 10 :

When a fraction equals zero :

10.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -2•(15y-7) —————————— • 10 = 0 • 10 10 

Now, on the left hand side, the 10 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape:
-2(15y-7)=0

Equations which are never true:

10.2Solve:-2=0

This equation has no solution.
A a non-zero constant never equals zero.

Solving a Single Variable Equation:

10.3Solve:15y-7 = 0Add 7 to both sides of the equation:
15y = 7
Divide both sides of the equation by 15:
y = 7/15 = 0.467

One solution was found :

y = 7/15 = 0.467

Simplify: y+6/4+y-3/5=5y-4/8 Tiger Algebra Solver (2024)

FAQs

What is the solution to the equation answer? ›

A solution to an equation is a value of a variable that makes a true statement when substituted into the equation. The process of finding the solution to an equation is called solving the equation. To find the solution to an equation means to find the value of the variable that makes the equation true.

How do you find the answer to algebra? ›

How to Solve an Algebra Problem
  1. Step 1: Write Down the Problem. ...
  2. Step 2: PEMDAS. ...
  3. Step 3: Solve the Parenthesis. ...
  4. Step 4: Handle the Exponents/ Square Roots. ...
  5. Step 5: Multiply. ...
  6. Step 6: Divide. ...
  7. Step 7: Add/ Subtract (aka, Combine Like Terms) ...
  8. Step 8: Find X by Division.

What is solution answers? ›

A solution is a hom*ogeneous mixture of one or more solutes dissolved in a solvent. solvent: the substance in which a solute dissolves to produce a hom*ogeneous mixture. solute: the substance that dissolves in a solvent to produce a hom*ogeneous mixture.

Is the solution in math the answer? ›

Important: Thus, a solution of an equation is an allowed value of the variable that makes the equation a true statement; the solution is the set of all allowed values that make the equation a true statement.

Is algebra hard math? ›

Algebra can be a hard subject because it is based on abstract concepts. You have to solve complex problems that involve variables and strong critical thinking and logical reasoning skills. Whether you find algebra hard or easy also depends on your foundational algebraic skills, practice skills, and attention span.

What is the hardest algebra class? ›

Abstract Algebra: This course introduces students to more abstract mathematical structures, such as groups, rings, and fields. It primarily revolves around proofs, and requires a solid understanding of prior math concepts to grasp the material fully.

Why am I so weak in algebra? ›

The primary cause of math difficulties is an inability to create a gestalt image for the concepts underlying math processes. Individuals often attempt to memorize facts instead of being able to think, reason, and problem solve with numbers.

Is there an app that solves algebra? ›

From easier algebra to the most complex calculus function equations, Algebra Math Solver provides you accurate solutions that you can trust. You can even take photos of your complex math equations and problems and the app will solve them for you!

How can I pass algebra? ›

Study Hard

Complete all of your assigned homework. You can also consider working on the extra practice problems in your textbook. The more algebra problems you solve, the better prepared you'll be for your exams. Give yourself enough time to work on homework and to prepare for exams.

What is PEMDAS in math? ›

Lesson Summary

PEMDAS is an acronym for the words parenthesis, exponents, multiplication, division, addition, subtraction. For any expression, all exponents should be simplified first, followed by multiplication and division from left to right and, finally, addition and subtraction from left to right.

Who invented 6? ›

The modern 6 can be traced back to the Brahmi numerals of India, which are first known from the Edicts of Ashoka c. 250 BCE.

Is BODMAS or PEMDAS correct? ›

PEMDAS term is used mainly in the US but in India and the UK, we call it as BODMAS. But there is no difference between them. The order of operations for brackets, orders, addition, subtraction, multiplication and division is the same for both the rule.

Is it 1 or 16? ›

Some people got 16 as the answer, and some people got 1. The confusion has to do with the difference between modern and historic interpretations of the order of operations. The correct answer today is 16. An answer of 1 would have been correct 100 years ago.

How to find the solution of an equation? ›

Bring the variable terms to one side of the equation and the constant terms to the other side using the addition and subtraction properties of equality. Make the coefficient of the variable as 1, using the multiplication or division properties of equality. isolate the variable and get the solution.

What is the solution to the system of equations answer? ›

The solution set to a system of equations will be the coordinates of the ordered pair(s) that satisfy all equations in the system. In other words, those values of x and y will make the equations true. Accordingly, when a system of equations is graphed, the solution will be all points of intersection of the graphs.

What is the solution of 30.16-17.56 5x? ›

Expert-Verified Answer

Thus, the value of x is 2.52.

What is the solution for the equation 5 3b 3 2b 2 5 2 b 3 2? ›

Summary: The solution to the equation 5/(3b3 -2b2 - 5) = 2/(b3 - 2) are b = 0 and b = 4.

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